Expressions in discrete mathematics
1 / 1 pts
The expression A∨B is not true unless A and B are both true propositions.
True
Correct!
False
1 / 1 pts
The expression C⊕D cannot be true if C and D have the same truth value.
Correct!
True
False
1 / 1 pts
The expression ¬F always has the opposite truth value from F.
Correct!
True
False
1 / 1 pts
The expression G⇒H cannot be true if G itself is a false proposition.
True
Correct!
False
1 / 1 pts
True or false: , where Q is the proposition that Arthur Conan Doyle wrote a prime number of Sherlock Holmes stories.
Correct!
True
False
There’s not enough information provided to answer this question, at least not in a reasonable amount of time, and with the facts in my possession.
1 / 1 pts
True or false: P⇒N, where P is the proposition that pigs can fly, and N is the proposition that there are 192 member states of the United Nations.
Correct!
True
False
There’s not enough information provided to answer this question, at least not in a reasonable amount of time, and with the facts in my possession.
1 / 1 pts
If is true for some propositions J and B, then is also definitely true.
Correct!
True
False
1 / 1 pts
If G⇒W is false for some propositions G and W, then G⊕W is definitelytrue.
Correct!
True
False
3 / 3 pts
Find binary values for X and Y such that (¬X⊕Y)∧¬Y is true:
X= 0 , Y= 0
Answer 1:
Correct!
0
Answer 2:
Correct!
0
3 / 3 pts
Find binary values for A, B, and C, such that ¬(¬A⇒(B⊕C))∧C istrue:
A= 0 (false) , B= 1 (true) , C= 1 (true)
Answer 1:
Correct!
0 (false)
Answer 2:
Correct!
1 (true)
Answer 3:
Correct!
1 (true)
2 / 2 pts
Supposes LOVES(x,y) is the proposition that person x loves person y. Which English sentence is a valid interpretation of the following assertion?
∀x&exists;yLOVES(x,y)
Nobody loves me.
I love everybody.
Correct!
Everybody loves somebody.
There’s some lovey dovey person who loves every single person in the world.
No matter who a person is, you can always find somebody who loves them.
1 / 1 pts
Let OlympicAthlete(x) be the proposition that x is or was an Olympic athlete, and let Male(x) be the proposition that x personally identifies with the male gender. True or false:
∀xOlympicAthlete(x)⇒Male(x)
True
Correct!
False
1 / 1 pts
Let HasMoreTwitterFollowersThan(x,y) be the proposition that Twitter user x has more followers than Twitter user y does (at this moment in time). True or false:
&exists;x&exists;yHasMoreTwitterFollowersThan(x,y)
Correct!
True
False
1 / 1 pts
&exists;x∀yHasMoreTwitterFollowersThan(x,y)
Correct Answer
True
You Answered
False
1 / 1 pts
∀x&exists;yHasMoreTwitterFollowersThan(x,y)
True
Correct!
False